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HJ21
@HJ21
March 2022
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Sobre função Afim,
Preciso da conta
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3478elc
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a) função decrescente
a < 0
(0,0) ( -1,3)
a= y2 - y1 ==> a = 3 - 0 ==> a = - 3
x2 - x1 -1 - 0
y = ax + b ==> -3.0 + b = 0 ==> b = 0
y = - x
a) função crescente
a > 0
(0,4) ( -1,1)
a= y2 - y1 ==> a = 1 - 4 ==> a = - 3 ==> a = 3
x2 - x1 -1 - 0 -1
y = ax + b ==> 3.0 + b = 4 ==> b = 4
y = 3x + 4
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Lista de comentários
Verified answer
a) função decrescente
a < 0
(0,0) ( -1,3)
a= y2 - y1 ==> a = 3 - 0 ==> a = - 3
x2 - x1 -1 - 0
y = ax + b ==> -3.0 + b = 0 ==> b = 0
y = - x
a) função crescente
a > 0
(0,4) ( -1,1)
a= y2 - y1 ==> a = 1 - 4 ==> a = - 3 ==> a = 3
x2 - x1 -1 - 0 -1
y = ax + b ==> 3.0 + b = 4 ==> b = 4
y = 3x + 4