January 2021 0 89 Report
Soit a≥2 on pose:x=a+2√(a-1 )
et y=a-2√(a-1)
1*montrer que∶x=(√(a-1 )+1)^2
et:y=(√(a-1)-1)^2
2**calculer:x.y
3***montrer que: √(a-1)-1≥0
4****déduire que : √x+√y=2√(a-1)
5*****simplifier : A=√(3+2√2)+√(3-2√2)
SVP AIDEZ MOI. MERCI D'AVANCE
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