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Coline62000
@Coline62000
April 2019
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Soit f la fonction définie sur R par f(x)=(2x+1)(x-3)+(2x+1)(3x+2) a) résoudre l'équation f(x)=8x² b)résoudre l'équation f(x)=4x+2 C'est urgent.. Merci beaucoup !
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F(x)=(2x+1)(x-3)+(2x+1)(3x+2)
=(2x+1)(x-3+3x+2)
=(2x+1)(4x-1)
=8x²+2x-1
f(x)=8x² donne 2x-1=0
donc x=1/2
f(x)=4x+2 donne 8x²+2x-1=4x+2
donc 8x²-2x-3=0
donc (2x+1)(4x-3)=0
donc x=-1/2 ou x=3/4
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Coline62000
Merci beaucoup c'est vraiment génial !
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=(2x+1)(x-3+3x+2)
=(2x+1)(4x-1)
=8x²+2x-1
f(x)=8x² donne 2x-1=0
donc x=1/2
f(x)=4x+2 donne 8x²+2x-1=4x+2
donc 8x²-2x-3=0
donc (2x+1)(4x-3)=0
donc x=-1/2 ou x=3/4