Articles
Register
Sign In
Search
julien778899
@julien778899
June 2021
1
113
Report
Suite géométrique et arithmétique SVP aidez moi
merci
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
caylus
Verified answer
Bonsoir,
1) voir fichier joint
2)
Comme V[n]=n(n+1)/2
V[n-1]=(n-1)*n/2
V[n-1]+n=(n²-n)/2+2n/2=(n²+n)/2=n(n+1)/2=V[n]
3)W[n]=(V[n])²={n(n+1)/2}²=n²(n²+2n+1)/4=(n^4+2n^3+n²)/4
4*(V[n])²+(n+1)^3)=n^4+2n^3+n²+4n^3+12n²+12n+4
=n^4+6n^3+13n²+12n+4
=n^4+2n^3+4n^3+8n²+5n²+10n+2n+4
=n^3(n+2)+4n²(n+2)+5n(n+2)+2(n+2)
=(n+2)(n^3+4n²+5n+2)=(n+2)(n^3+2n^2+2n^2+4n+n+2)
=(n+2)[n²(n+2)+2n(n+2)+1(n+2)]
=(n+2)(n+2)(n²+2n+1)
=(n+1)²*(n+2)²
=> (V[n])²+(n+1)²={(n+1)/n+2)/2}²={V[n+1]}²
W[n+1]={V[n+1]}²
1 votes
Thanks 1
More Questions From This User
See All
julien778899
June 2021 | 0 Respostas
J'ai besoin d'aide,Pour le 1er casa)2eme casb)
Responda
julien778899
June 2021 | 0 Respostas
Aidez moi SVP URGENTVecteurs
Responda
julien778899
June 2021 | 0 Respostas
Responda
julien778899
June 2021 | 0 Respostas
Responda
julien778899
January 2021 | 0 Respostas
Responda
julien778899
January 2021 | 0 Respostas
Responda
julien778899
January 2021 | 0 Respostas
Responda
Julien778899
April 2019 | 0 Respostas
Responda
Julien778899
April 2019 | 0 Respostas
Responda
Julien778899
April 2019 | 0 Respostas
Responda
×
Report "Suite géométrique et arithmétique SVP aidez moi merci.... Pergunta de ideia de julien778899"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Bonsoir,1) voir fichier joint
2)
Comme V[n]=n(n+1)/2
V[n-1]=(n-1)*n/2
V[n-1]+n=(n²-n)/2+2n/2=(n²+n)/2=n(n+1)/2=V[n]
3)W[n]=(V[n])²={n(n+1)/2}²=n²(n²+2n+1)/4=(n^4+2n^3+n²)/4
4*(V[n])²+(n+1)^3)=n^4+2n^3+n²+4n^3+12n²+12n+4
=n^4+6n^3+13n²+12n+4
=n^4+2n^3+4n^3+8n²+5n²+10n+2n+4
=n^3(n+2)+4n²(n+2)+5n(n+2)+2(n+2)
=(n+2)(n^3+4n²+5n+2)=(n+2)(n^3+2n^2+2n^2+4n+n+2)
=(n+2)[n²(n+2)+2n(n+2)+1(n+2)]
=(n+2)(n+2)(n²+2n+1)
=(n+1)²*(n+2)²
=> (V[n])²+(n+1)²={(n+1)/n+2)/2}²={V[n+1]}²
W[n+1]={V[n+1]}²