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TDx
@TDx
January 2021
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Sur une droite graduée, on considère les points A ( - 8), B ( - 11), C (31,5), D ( -8,5) et E ( -7). Calculez les distances AC, BE, BC, CD, CE et AE.
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GHANAMI
Bonsoir voici une solution :
AC=XC -XA =(31.5 )-(-8 ) =31.5+8 =39.5
BE=XE -XB =(-7 )-(-11 ) =-7+11 =4
BC=XC -XB =( 31.5)-(-11 ) =31.5+11=42.5
CD=XD -XC =(-8.5 )-(31.5 ) =-40
CE=XE -XC =(-7 )-(31.5 ) = -38.5
AE=XE -XA =
( -7)-(-8 ) =-7+8 =1
3 votes
Thanks 4
GHANAMI
remarque : ne pas oublier qu'une distance est toujours positive
melissa223
AC= 31,5- (-8)
BE= -7-11 ne pas oublier qu'une distance est toujours positive
BC= 31,5- (-11)
CD= 31,5- (-8,5)
CE= C-E
AE= A-E
1 votes
Thanks 2
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AC=XC -XA =(31.5 )-(-8 ) =31.5+8 =39.5
BE=XE -XB =(-7 )-(-11 ) =-7+11 =4
BC=XC -XB =( 31.5)-(-11 ) =31.5+11=42.5
CD=XD -XC =(-8.5 )-(31.5 ) =-40
CE=XE -XC =(-7 )-(31.5 ) = -38.5
AE=XE -XA =( -7)-(-8 ) =-7+8 =1
BE= -7-11 ne pas oublier qu'une distance est toujours positive
BC= 31,5- (-11)
CD= 31,5- (-8,5)
CE= C-E
AE= A-E