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antoinegonzalez
@antoinegonzalez
June 2021
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svp 15 PTS pour celui ki y arrive
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bnitchandikou
OH² + AH² = AO² ⇒ AH² = AO² - OH² ⇒ AH = √(AO² - OH²) = √(1.3² - 1.2²) = √0.25⇒
AH = 0.5 donc AB = 2AH = 1
l'aire de la section ABCD = AB*AD soit 1*5.3 =
5.3cm²
L'aire de la base du cylindre = AO²*π ≈ 1.3²*3.14 =
5.3cm²
Conclusion, Les deux aires sont égales.
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Lista de comentários
l'aire de la section ABCD = AB*AD soit 1*5.3 = 5.3cm²
L'aire de la base du cylindre = AO²*π ≈ 1.3²*3.14 = 5.3cm²
Conclusion, Les deux aires sont égales.