Verified answer

Bonsoir,

Réponse :

[tex]A = (x-\sqrt{2}) ^{2} +2x\sqrt{8} \\A = x^{2} -2x\sqrt{2}+(\sqrt{2})^2 +2x\sqrt{8}\\A = x^{2} -x\sqrt{8} +2+2x\sqrt{8} \\A = x^{2} +x\sqrt{8} +2\\A = x^{2} +2x\sqrt{2} +(\sqrt{2})^2 \\\boxed{A=(x+\sqrt{2})^2 }[/tex]

N.B :

[tex]\sqrt{8}=\sqrt{4}\times\sqrt{2} =2\sqrt{2}[/tex]

[tex](a+b)^2=a^2+2ab+b^2[/tex]

[tex](a-b)^2=a^2-2ab+b^2[/tex]

En espérant t'avoir aidé, bonne continuation ! :)