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loloe6
@loloe6
June 2021
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Svp aidez moi!!! C'est pour un dm de maths de 3ème
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winner123
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Bonjour
Périmètre ABC = AB + BC + AC
154 = x + 56 + 65
154 - 56 - 65 = x
33 = x
donc AB = 33 m
DC = 144 - 65 - 16
dc = 63 m
DC= 63 m
périmètre ABCD = 33 + 56 +63 + 16 = 168 m
2) AC² = AD² + DC²
65² = 16² + 63²
4 225 = 256 + 3 969
4 225 = 4 225
Pythagore est vérifié, le triangle est bien rectangle
Aire ABC = ( 33 x 56) / 2
aire = 924 m²
Aire ACD = ( 16 x 63) / 2
aire = 504 m²
aire totale = 924 + 504 = 1 428 m²
clôture = 168 x 0.85 = 142.80 €
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Verified answer
BonjourPérimètre ABC = AB + BC + AC
154 = x + 56 + 65
154 - 56 - 65 = x
33 = x
donc AB = 33 m
DC = 144 - 65 - 16
dc = 63 m
DC= 63 m
périmètre ABCD = 33 + 56 +63 + 16 = 168 m
2) AC² = AD² + DC²
65² = 16² + 63²
4 225 = 256 + 3 969
4 225 = 4 225
Pythagore est vérifié, le triangle est bien rectangle
Aire ABC = ( 33 x 56) / 2
aire = 924 m²
Aire ACD = ( 16 x 63) / 2
aire = 504 m²
aire totale = 924 + 504 = 1 428 m²
clôture = 168 x 0.85 = 142.80 €