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aaleexiiaah
@aaleexiiaah
June 2021
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SVP aiiiidez moi j'y arrive pas
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danielwenin
Verified answer
1. par Pythagore: AH^2 = 36×2 - 9.2 = 2 (36 - 9) = 54
AH = 3V6
AIRE= 3V6 x 3V2 = 18V3
2) FH = V(36+36) =V72 = 6V2
AFH est équilatéral car AF =AH = FH = diagonale des faces du cube
aire = 18V3
BDHF est un rectangle d'aire 6x 6V2 = 36V2
il te reste à calculer
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Verified answer
1. par Pythagore: AH^2 = 36×2 - 9.2 = 2 (36 - 9) = 54AH = 3V6
AIRE= 3V6 x 3V2 = 18V3
2) FH = V(36+36) =V72 = 6V2
AFH est équilatéral car AF =AH = FH = diagonale des faces du cube
aire = 18V3
BDHF est un rectangle d'aire 6x 6V2 = 36V2
il te reste à calculer