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Farah234
@Farah234
May 2019
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Svp j'ai besoin d'aide j'essaie mainte fois et je n'arrive pas svp une petite aide et merci d'avance
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scoladan
Verified answer
Bonjour,
f(x) = 1 + [√(x² + 1) - x][√(x² + 1) + x]/[√(x² + 1) + x] (x > 0)
= 1 + [(x² + 1) - x²]/[√(x² + 1) + x]
= 1 + 1/[√(x² + 1) + x]
lim [√(x² + 1) + x] en +∞ = +∞
⇒ lim 1/[√(x² + 1) + x] = 0+
⇒ lim f(x) = 1
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farah234
merci
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Lista de comentários
Verified answer
Bonjour,f(x) = 1 + [√(x² + 1) - x][√(x² + 1) + x]/[√(x² + 1) + x] (x > 0)
= 1 + [(x² + 1) - x²]/[√(x² + 1) + x]
= 1 + 1/[√(x² + 1) + x]
lim [√(x² + 1) + x] en +∞ = +∞
⇒ lim 1/[√(x² + 1) + x] = 0+
⇒ lim f(x) = 1