Svp qui peut m’aider.... Pergunta de ideia dekeziao

June 2021 1 24 Report

Svp qui peut m’aider

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barthyanastro007

❂ Salut ❂

✎ Données :

$A = 12 \: cm$

$h_{(1)} = 8\: cm$

$h_{(2)} = 8,5\: cm$

✍ Résolution :

Cherchons le volume d'eau sans le caillou :

On a :

$A = 12 \: cm$

$h_{(1)} = 8\: cm$

Alors :

$V_{(1)} = (12 \times 8 \times 12)\: {cm}^{3}$

$V_{(1)} = 1152 \: {cm}^{3}$

Cherchons le volume d'eau avec le caillou :

On a :

$A = 12 \: cm$

$h_{(2)} = 8,5\: cm$

Alors :

$V_{(2)} = (12\times 8,5\times 12)\: {cm}^{3}$

$V_{(2)} = 1224 \: {cm}^{3}$

Calculons le volume du caillou :

$V_{(C)} = V_{(2)} - V_{(1)}$

$V_{(C)} = (1224 - 1152 )\: {cm}^{3}$

$\boxed{\boxed{V_{(C)} = 72\: {cm}^{3}}}$

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