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Ley2wice
@Ley2wice
April 2019
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SVP SVP SVP URGENT!Résoudre le système de 3 equatins a 3 inconnues
x-3y=8
4x+2y=-10
2x-6+4z=24
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anylor
X= 8 +3y
4( 8+3y) +2y = -10 => 32 +12y +2y =-10 => 14y = -10-32= -42
y = -42/14 => y = - 3
x= 8 +3y => x= 8 + 3 * -3 =- 1
2x-6+4z=24 => 4z = 24 + 6 - 2x = 24 + 6 - 2*( -1) = 32
4z = 32 => z = 32 /4 = 8
donc
x = -1
y = - 3
z = 8
3 votes
Thanks 2
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4( 8+3y) +2y = -10 => 32 +12y +2y =-10 => 14y = -10-32= -42
y = -42/14 => y = - 3
x= 8 +3y => x= 8 + 3 * -3 =- 1
2x-6+4z=24 => 4z = 24 + 6 - 2x = 24 + 6 - 2*( -1) = 32
4z = 32 => z = 32 /4 = 8
donc x = -1
y = - 3
z = 8