Os ângulos são [tex]a=120^{\circ};b=60^{\circ};c=70^{\circ};d=50^{\circ};e=50^{\circ}[/tex]
Para responder essa questão, vamos usar os conhecimentos de retas paralelas cortas por uma reta transversal.
[tex]e+130^{\circ}=180^{\circ}\\\\e=180^{\circ}-130^{\circ}\\\\\boxed{e=50^{\circ}}[/tex]
[tex]d=e\\\\ \boxed{d=50^{\circ}}[/tex]
[tex]\boxed{a=120^{\circ}}[/tex]
[tex]b+a=180^{\circ}\\\\b+120^{\circ}=180^{\circ}\\\\b=180^{\circ}-120^{\circ}\\\\\boxed{b=60^{\circ}}[/tex]
[tex]b+c+d=180^{\circ}\\\\60^{\circ}+c+50^{\circ}=180^{\circ}\\\\c+110^{\circ}=180^{\circ}\\\\c=180^{\circ}-110^{\circ}\\\\\boxed{c=70^{\circ}}[/tex]
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Os ângulos são [tex]a=120^{\circ};b=60^{\circ};c=70^{\circ};d=50^{\circ};e=50^{\circ}[/tex]
Para responder essa questão, vamos usar os conhecimentos de retas paralelas cortas por uma reta transversal.
[tex]e+130^{\circ}=180^{\circ}\\\\e=180^{\circ}-130^{\circ}\\\\\boxed{e=50^{\circ}}[/tex]
[tex]d=e\\\\ \boxed{d=50^{\circ}}[/tex]
[tex]\boxed{a=120^{\circ}}[/tex]
[tex]b+a=180^{\circ}\\\\b+120^{\circ}=180^{\circ}\\\\b=180^{\circ}-120^{\circ}\\\\\boxed{b=60^{\circ}}[/tex]
[tex]b+c+d=180^{\circ}\\\\60^{\circ}+c+50^{\circ}=180^{\circ}\\\\c+110^{\circ}=180^{\circ}\\\\c=180^{\circ}-110^{\circ}\\\\\boxed{c=70^{\circ}}[/tex]
Saiba mais em:
https://brainly.com.br/tarefa/6594204
https://brainly.com.br/tarefa/4179168