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Smades
@Smades
January 2021
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bonjour à tous/tes
merci de bien vouloir m'aider pour l'exercice 56.
cordialement
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meemameema
Verified answer
Une fonction linéaire est de la fonction f(x) = ax
d1 : f(1) = 1xa = 3 d'ou x = 3/1 donc x=3 et
f(x) = 3x
d2 : g(3) = 3xa = 1 d'ou x = 1/3 donc x= 1/3 et
g(x) = 1/3x
d2 : h(-4) = -4xa = 2 d'ou x = - 2/4 soit x= - 1/2 et
h(x) = - 1/2x
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Bonsoir, aidez-moi svp, merci. Cordialement Smades
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Bonsoir. Aidez moi svp c'est pour lundi, urgent !
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Aidez moi svp c'est pour lundi
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Lista de comentários
Verified answer
Une fonction linéaire est de la fonction f(x) = axd1 : f(1) = 1xa = 3 d'ou x = 3/1 donc x=3 et f(x) = 3x
d2 : g(3) = 3xa = 1 d'ou x = 1/3 donc x= 1/3 et g(x) = 1/3x
d2 : h(-4) = -4xa = 2 d'ou x = - 2/4 soit x= - 1/2 et h(x) = - 1/2x