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Chocolol
@Chocolol
January 2021
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Pouvez vous me résoudre ces deux petites inéquations ? je vous remercie d'avance >.< !
x²+ x - 1 [tex] \leq [/tex] 0.
et 2x < x² - 1.
j'ai vraiment du mal alors merci a ceux qui prendront la peine de m'aider ^w^ !
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antgaillard
X^2+x-1 < 0
Delta=5
x1=(-1-sqrt5)/2
x2=(-1+sqrt5)/2
Entre ces deux valeurs, x^2+x-1<0
2x<x^2-1
0<x^2-2x-1
x^2+2x-1>0
delta= 8
x1=(-2-sqrt8)/2
x2=(-2+sqrt8)/2
Entre ces deux valeurs, le résultat sera supérieur à 0..
2 votes
Thanks 1
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Lista de comentários
Delta=5
x1=(-1-sqrt5)/2
x2=(-1+sqrt5)/2
Entre ces deux valeurs, x^2+x-1<0
2x<x^2-1
0<x^2-2x-1
x^2+2x-1>0
delta= 8
x1=(-2-sqrt8)/2
x2=(-2+sqrt8)/2
Entre ces deux valeurs, le résultat sera supérieur à 0..