Bonjour,
1)
E = (x+1)² + (x+1)(2x-3)
= x²+2x+1+2x²-3x+2x-3
= 3x²+x-2
2)
= (x+1)(x+1)+(x+1)(2x-3)
= (x+1)(x+1+2x-3)
= (x+1)(3x-2)
3) (x+1)(3x-2) = 0
⇒ x+1=0 ou 3x-2=0
⇒ x=-1 ou 3x=2
⇒ x=-1 ou x=2/3
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Bonjour,
1)
E = (x+1)² + (x+1)(2x-3)
= x²+2x+1+2x²-3x+2x-3
= 3x²+x-2
2)
E = (x+1)² + (x+1)(2x-3)
= (x+1)(x+1)+(x+1)(2x-3)
= (x+1)(x+1+2x-3)
= (x+1)(3x-2)
3) (x+1)(3x-2) = 0
⇒ x+1=0 ou 3x-2=0
⇒ x=-1 ou 3x=2
⇒ x=-1 ou x=2/3