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clarissey
@clarissey
January 2021
1
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Pourriez-vous m'aider SVP
Développer puis réduire les expressions suivantes:
1) ([tex] a). ( \frac{1}{2}x + 4)^{2}
2). (3x - 1)^{2}
3). (2x - 3) (2x + 3)
4). (4x - 3)^{2} - (4x + 3)^{2}
5). x (x + 1) (-x + 2)
Factoriser les expressions suivantes
a) 4 x^{2} -4x+1
b) (2x+6)^{2} -25
c) (x-1)(x+7) + (x-1)(2x+3)
d) (4x-3)^{2} - (4x+3) ^{2}
e) (3x-4) - 2(3x-4) ^{2}
[/tex]
f) [tex] \frac{1}{4} x^{2} - \frac{1}{3}x+ \frac{1}{9} [/tex]
merci pour votre aide
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winner123
Verified answer
Bonjour
a = 1/4 x² + 8/2 x + 16
b = 9 x² - 6 x + 1
c = 16 x² - 24 x + 9 - (16 x² + 24 x + 9) = 16 x² - 24 x + 9 - 16 x² - 24 x - 9
= - 48 x
d = (x²+ x ) ( - x + 2) = - x³ + 2 x² - x² + 2 x = - x³ + x² + 2 x
a = ( 2 x - 1)²
b = ( 2 x + 6 - 5) ( 2 x + 6 + 5) = ( 2 x + 1) ( 2 x + 11)
c = ( x - 1) ( x + 7 + 2 x + 3) = ( x - 1) ( 3 x + 10)
d = 16 x² - 9
f = (1/2 x - 13)²
1 votes
Thanks 1
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Verified answer
Bonjoura = 1/4 x² + 8/2 x + 16
b = 9 x² - 6 x + 1
c = 16 x² - 24 x + 9 - (16 x² + 24 x + 9) = 16 x² - 24 x + 9 - 16 x² - 24 x - 9
= - 48 x
d = (x²+ x ) ( - x + 2) = - x³ + 2 x² - x² + 2 x = - x³ + x² + 2 x
a = ( 2 x - 1)²
b = ( 2 x + 6 - 5) ( 2 x + 6 + 5) = ( 2 x + 1) ( 2 x + 11)
c = ( x - 1) ( x + 7 + 2 x + 3) = ( x - 1) ( 3 x + 10)
d = 16 x² - 9
f = (1/2 x - 13)²