Articles
Register
Sign In
Search
gigi081
@gigi081
January 2021
1
37
Report
Bonjour pouvez vous m'aider sur une fonction ?
C'est une fonction dérivable de type f'(x)
[tex] x^{2} +3x-7/ x^{2} +4x+1[/tex] merci
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
isapaul
Verified answer
Bonjour,
f(x) = (x²+3x-7) / (x²+4x+1)
f ' (x) = [ (2x+3)(x²+4x+1) - (x²+3x-7)(2x+4)] / (x² +4x+1)²
f ' (x) = (x² +16x +31) / [ 3(x^4 +16x² +1)]
Bonne journée
2 votes
Thanks 1
More Questions From This User
See All
gigi081
January 2021 | 0 Respostas
Responda
gigi081
January 2021 | 0 Respostas
Responda
gigi081
January 2021 | 0 Respostas
SVP !!! Urgent pour Lundi je dois faire un dialogue en Anglais ( 150 mots) il faut persuader ue personne de venir en Angleterre mais elle ne veut pas Merci d'avance
Responda
gigi081
January 2021 | 0 Respostas
Responda
gigi081
January 2021 | 0 Respostas
Responda
gigi081
January 2021 | 0 Respostas
Responda
gigi081
January 2021 | 0 Respostas
Responda
gigi081
January 2021 | 0 Respostas
Responda
gigi081
January 2021 | 0 Respostas
Responda
gigi081
January 2021 | 0 Respostas
Responda
×
Report "Bonjour pouvez vous m'aider sur une fonction ? C'est une fonction dérivable de type f'(x) [tex] x^{2.... Pergunta de ideia de gigi081"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Bonjour,f(x) = (x²+3x-7) / (x²+4x+1)
f ' (x) = [ (2x+3)(x²+4x+1) - (x²+3x-7)(2x+4)] / (x² +4x+1)²
f ' (x) = (x² +16x +31) / [ 3(x^4 +16x² +1)]
Bonne journée