calcule: [tex]d) C_{12,6} + C _{8,2}[/tex] URGENTE POR FAVOR.... Pergunta de ideia dedeniloira

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12! 8!
  ------------ + ------------
6! (12 - 6)! 2! (8 - 2)!
====================================
12! 8!
--------------- + ----------
  6! 6! 2! 6!
====================================
12.11.10.9.8.7.6! 8.7.6!
----------------------- + ------------
6! 6! 2! 6 !
====================================
12.11.10.9.8.7 8.7
--------------------- + -------------------
6.5.4.3.2 2
====================================
12.11.10.9.8.7
--------------------------- + 4 . 7
120
====================================
12 . 11 . 7 + 28
====================================
924 + 28 = 952

Resposta = 952

AltairAlves

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Combinação:

$C_{12,6} \ + \ C_{8,2}$

Determinando $C_{12,6}$ :

$C_{12,6} = \frac{12!}{6!(12-6)!}$

$C_{12,6} = \frac{12.11.10.9.8.7.6!}{6!6!}$

Eliminando 6! com 6!, numerador e denominador:

$C_{12,6} = \frac{12.11.10.9.8.7}{6!}$

$C_{12,6} = \frac{12.11.10.9.8.7}{720}$

Simplificando 720 com o 8, 9 e 10, temos:

$C_{12,6} = \frac{12.11.7}{1}$

$C_{12,6} = 12 \ . \ 11 \ . \ 7$

$C_{12,6} = \ 924$

Determinando $C_{8,2}$ :

$C_{8,2} = \frac{8!}{2!(8-2)!}$

$C_{8,2} = \frac{8.7.6!}{2!6!}$

Eliminando 6! com 6!, numerador e denominador:

$C_{8,2} = \frac{8.7}{2!}$

$C_{8,2} = \frac{56}{2}$

$C_{8,2} = \ 28$

Realizando a adição:

$C_{12,6} \ + \ C_{8,2}$

924 + 28 = 952

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POR FAVOR ME AJUDEM? CALCULE A) 0!+4! B)5! - 4! URGENTEE

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