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jheny3801
@jheny3801
March 2022
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Resolva a inequação:
1-a)[tex] \frac{x}{2} + \frac{x}{3} [/tex] ≥ [tex] \frac{-x}{6} [/tex]
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ramoncatim
3x+2x> -x
6x>0
x>1\6
E isso
1 votes
Thanks 1
gabysgomes
3x+2x> -x
6x>0
x
≥ 0
Desculpa a demoraaa hsausuhasuhasu
1 votes
Thanks 1
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Lista de comentários
6x>0
x>1\6
E isso
3x+2x> -x
6x>0
x≥ 0
Desculpa a demoraaa hsausuhasuhasu