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kahrausis
@kahrausis
March 2022
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Calcule a determinante da matriz:[tex] \left[\begin{array}{ccc}1&-3&-6\\4&5&8\\0&2&-2\end{array}\right] [/tex]
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alan11001100
Utilizando a regra de sarrus temos;
Diagonal Principal: (1*5*-2)+(-3*8*0)+(-6*4*2)=-58
Diagonal Secundaria: (0*5*-6)+(2*8*1)+(-2*4*-3)=40
-58+(-40) = -98
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kahrausis
muito obrigada <3
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kahrausis
April 2022 | 0 Respostas
Calcule o determinante da matriz abaixo: 2 -5 -8 9
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Diagonal Principal: (1*5*-2)+(-3*8*0)+(-6*4*2)=-58
Diagonal Secundaria: (0*5*-6)+(2*8*1)+(-2*4*-3)=40
-58+(-40) = -98