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purplemonkey1d
@purplemonkey1d
October 2020
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Calcule as seguintes divisões:
a) [tex] (4a^{4} - 2a + 8a) : (2a)[/tex]
b) [tex] (9x^{6} - 12x^{5} + 18x^{3} - x^{2}) : (3x^{3}) [/tex]
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laurelidb
A)
b)
a)
a4 - 2a + 8a
=
a4 + 6a
==>
a(a3 +6)
==>
a3 + 6
2a 2a 2a 2
b)
9x6 - 12x5 + 18x3 - x2
=
x2(9x4 - 12x3 + 18x - 1)
=
(9x4 - 12x3 + 18x - 1)
3x3 3x3 3x
1 votes
Thanks 0
3478elc
Verified answer
A)
2a³ - 1 +4
b)
3x³ -4x² + 6 -3x
2 votes
Thanks 0
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Lista de comentários
b)
a) a4 - 2a + 8a = a4 + 6a ==> a(a3 +6) ==> a3 + 6
2a 2a 2a 2
b) 9x6 - 12x5 + 18x3 - x2 = x2(9x4 - 12x3 + 18x - 1) = (9x4 - 12x3 + 18x - 1)
3x3 3x3 3x
Verified answer
A)2a³ - 1 +4
b)
3x³ -4x² + 6 -3x