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l52off
@l52off
May 2023
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Bonjour, je ne sais pas comment on fait pour résoudre cet exercice.
46 [Chercher.] Pour chaque cas, donner un encadrement de x², ou une inégalité vérifiée par x².
1)
[tex] - 2 < x \leqslant 7[/tex]
2)
[tex]4 \leqslant x < 7[/tex]
3)
[tex]x > - 3[/tex]
4)
[tex]x < - 2[/tex]
5)
[tex] - 6 \leqslant x < 3[/tex]
6)
[tex] - 11 < x \leqslant - 2[/tex]
Merci d'avance.
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kawtharqsair
Réponse:
1)-2<x<7
−2×2<x×2⩽7×2
-4<2x<14
0 votes
Thanks 1
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Réponse:
1)-2<x<7
−2×2<x×2⩽7×2
-4<2x<14