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edeline71
@edeline71
April 2022
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[tex] {e}^{x} + 2 {e}^{ - x} > 0[/tex]
Qn pour m'aider à résoudre ceci ?
Merci d'avance
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elaqaniachraf
Réponse :e^x+2e^-x > 0= e^x*1 + 2*e^x*e^-1 > 0= e^x(1+2e^-1) > 0
1 votes
Thanks 1
elaqaniachraf
j'espères tu comprends
elaqaniachraf
puissances c'est "^"
elaqaniachraf
je te laisse continuez car c'est facile après
elaqaniachraf
tu trouveras normalement x>0 on le justifiant
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