Escreva o inverso de cada um destes núme- ros racionais:
a)
[tex] \frac{7}{8} [/tex]
b)
[tex] - \frac{5}{12} [/tex]
c)
[tex] - \frac{17}{4} [/tex]
d) 9
e) – 16
f)
[tex] - \frac{1}{10} [/tex]
(Vale 50 pontos!)
a)
[tex] \frac{7}{8} [/tex]
b)
[tex] - \frac{5}{12} [/tex]
c)
[tex] - \frac{17}{4} [/tex]
d) 9
e) – 16
f)
[tex] - \frac{1}{10} [/tex]
(Vale 50 pontos!)
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Verified answer
✅ Sabendo que o inverso ou inverso multiplicativo ou recíproco de um número pode ser calculado pela seguinte fórmula:
[tex]\Large\displaystyle\text{$\begin{gathered} I(n) = \frac{1}{n}\end{gathered}$}[/tex]
Então, calculando os inverso multiplicativos, temos:
[tex]\Large\displaystyle\text{$\begin{gathered} I\bigg(\frac{7}{8}\bigg) = \frac{1}{\dfrac{7}{8}} = 1\cdot\frac{8}{7} = \frac{8}{7}\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} I\bigg(-\frac{5}{12}\bigg) = \frac{1}{-\dfrac{5}{12}} = 1\cdot\bigg(-\frac{12}{5}\bigg) = -\frac{12}{5}\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} I\bigg(-\frac{17}{4}\bigg)= \frac{1}{-\dfrac{17}{4}} = 1\cdot\bigg(-\frac{4}{17}\bigg) = -\frac{4}{17}\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} I(9) = \frac{1}{9}\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} I(-16) = -\frac{1}{16}\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} I\bigg(-\frac{1}{10}\bigg) = \frac{1}{-\dfrac{1}{10}} = 1\cdot\bigg(-\frac{10}{1}\bigg) = -10\end{gathered}$}[/tex]
[tex]\LARGE\displaystyle\text{$\begin{gathered} \underline{\boxed{\boldsymbol{\:\:\:Bons \:estudos!!\:\:\:Boa\: sorte!!\:\:\:}}}\end{gathered}$}[/tex]
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