(UFRS) A equação da circunferência de diâmetro AB , com A (3, 1) e B (1, -3), é: a) x2 + y2 + 4x – 2y – 15 = 0
b) x2 + y2 – 4x + 2y – 15 = 0
c) x2 + y2 – 4x + 2y = 0
d) x2 + y2 + 4x + 2y = 0
e) x2 + y2 – 2x + 4y = 0
b) x2 + y2 – 4x + 2y – 15 = 0
c) x2 + y2 – 4x + 2y = 0
d) x2 + y2 + 4x + 2y = 0
e) x2 + y2 – 2x + 4y = 0
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