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katlleen
@katlleen
October 2020
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um aviao parte do reppouso com uma aceleraçao contante de 2m\s. que velocidade atinge, apos percorrer 36m ?
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pjfaria
V² = Vo² + 2 * a * /\S
V² = 0 + 2*2 * 36
V² = 144
*************
V = 12m/s
*************
2 votes
Thanks 2
thaisrroseno
V ² = v0² + 2 a Δs
v² = 0 + 2 2 36
v² = 144
v = √144 = 12 m/s
1 votes
Thanks 1
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Lista de comentários
V² = 0 + 2*2 * 36
V² = 144
*************
V = 12m/s
*************
v² = 0 + 2 2 36
v² = 144
v = √144 = 12 m/s