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Fyzynko
@Fyzynko
October 2020
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um triangulo cuja hipotenusa mede x e seus catetos 5 e (7-x), quanto vale x?
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LEINHA7
hipotenusa mede x e seus catetos 5 e (7-x)
a² = b² + c²
x² = 5² + (7-x)²
x² = 25 + 49 -14x + x²
x² + 14x - x² = 25 + 49
14x = 74
x = 74/14
1 votes
Thanks 1
3478elc
Verified answer
H^2=c^2 +c^2
x^2=5^2 + (7-x)^2
x^2=25+49-14x +x^2
x^2-x^2+14x=74
14x=74
x=74\14
x=37\7
x=5,3
1 votes
Thanks 1
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Lista de comentários
hipotenusa mede x e seus catetos 5 e (7-x)
a² = b² + c²
x² = 5² + (7-x)²
x² = 25 + 49 -14x + x²
x² + 14x - x² = 25 + 49
14x = 74
x = 74/14
Verified answer
H^2=c^2 +c^2x^2=5^2 + (7-x)^2
x^2=25+49-14x +x^2
x^2-x^2+14x=74
14x=74
x=74\14
x=37\7
x=5,3