Resposta:
ΔV = 3,6 mL
Explicação:
Dilatação linear
L₀ = 20 cm = 200 mm
t₀ = 10 °C
ΔL = 0,44 mm
t = 110 °C
α = ?
[tex]\Delta L = L_{0}.\alpha .\Delta t\\\\0,44 = 200*\alpha *(110-10)\\\\0,44 = 200*\alpha *100\\\\0,44 = 20000\alpha\\\\\frac{0,44}{20000} =\alpha \\\\\alpha =\frac{44.10^{-2}}{2.10^4} \\\\\alpha =22.10^{-2-4}\\\\\alpha =22.10^{-6}^{o}C^{-1}[/tex]
γ = 3α ==> γ = 66.10⁻⁶ °C⁻¹
Dilatação volumétrica
ΔV = ?
V₀ = 1000 mL
t₀ = 50 °C
t = 100 °C
ΔV = V₀.γ.Δt
ΔV = 1000 * 66.10⁻⁶ * (100 - 50)
ΔV = 1000 * 66.10⁻⁶ * 50
ΔV = 3300000.10⁻⁶
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Resposta:
ΔV = 3,6 mL
Explicação:
Dilatação linear
L₀ = 20 cm = 200 mm
t₀ = 10 °C
ΔL = 0,44 mm
t = 110 °C
α = ?
Dilatação linear
[tex]\Delta L = L_{0}.\alpha .\Delta t\\\\0,44 = 200*\alpha *(110-10)\\\\0,44 = 200*\alpha *100\\\\0,44 = 20000\alpha\\\\\frac{0,44}{20000} =\alpha \\\\\alpha =\frac{44.10^{-2}}{2.10^4} \\\\\alpha =22.10^{-2-4}\\\\\alpha =22.10^{-6}^{o}C^{-1}[/tex]
γ = 3α ==> γ = 66.10⁻⁶ °C⁻¹
Dilatação volumétrica
ΔV = ?
V₀ = 1000 mL
t₀ = 50 °C
t = 100 °C
ΔV = V₀.γ.Δt
ΔV = 1000 * 66.10⁻⁶ * (100 - 50)
ΔV = 1000 * 66.10⁻⁶ * 50
ΔV = 3300000.10⁻⁶
ΔV = 3,6 mL