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LuanaAguiar
@LuanaAguiar
March 2022
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Uma força constante e horizontal de intensidade de 10N movimenta um corpo, numa trajetória horizontal ,por 30m .Calcule o trabalho realizado por essa força.
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nandofilho10
TRABALHO = FORÇA . DESLOCAMENTO
T = 10 . 30 =
300 J
2 votes
Thanks 1
IsabelaBorges
F=10N
d=30m
J=?
J=f.d
J=10.30
J=300 J
1 votes
Thanks 1
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Lista de comentários
T = 10 . 30 = 300 J
d=30m
J=?
J=f.d
J=10.30
J=300 J