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Joof973
@Joof973
May 2019
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Une personne pour m'aider pour l'exercice 48. Thank you verry much ( équations et inéquations 3ème )
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MAHAM
Verified answer
Hello!!
a) calcul de AE
AENT est un carre donc P=C×4
C=P/4
C=14
or AE=EN=NT=TA=C
donc AE=14 cm
b)
PENTA est un pentagone alors P=AP+PE+EN+NT+TA
or PAE est isocele en P d'ou PA=PE
Ainsi AP+AP+14+14+14=60
2AP=60-(14+14+14)
2AP=18
AP=18/2
AP=9cm
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joof973
Thanks !!!
MAHAM
don't mention it !!
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Lista de comentários
Verified answer
Hello!!a) calcul de AE
AENT est un carre donc P=C×4
C=P/4
C=14
or AE=EN=NT=TA=C
donc AE=14 cm
b)
PENTA est un pentagone alors P=AP+PE+EN+NT+TA
or PAE est isocele en P d'ou PA=PE
Ainsi AP+AP+14+14+14=60
2AP=60-(14+14+14)
2AP=18
AP=18/2
AP=9cm