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Laura23
@Laura23
May 2019
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URGENT !!!! Bonjour j'ai besoin d'aide s.v.p Merci d'avance
Resoudre dans |R les inéquations proposées.
x (3 -x ) (2x + 1 ) > 0
(2x - 1) (4 -5x) (x+2) 《 0 ( supérieur ou égal)
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nadiab
Bonjour,
x (3 -x ) (2x + 1 ) > 0
x=0
ou
-x+3=0 => x=3
ou
2x+1=0 => x=-1/2
x -
∞ -1/2 0 3 +∞
x - -
Ф + I +
-x+3 + I + I +
Ф -
2x+1 -
Ф
+ I + I +
P + I - I + I -
S= ] -
∞; -1/2 [ ∪ ] 0;3[
(2x - 1) (4 -5x) (x+2) tu fais pareil mais fais attention aux crochets, ils sont fermés.
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x (3 -x ) (2x + 1 ) > 0
x=0
ou
-x+3=0 => x=3
ou
2x+1=0 => x=-1/2
x -∞ -1/2 0 3 +∞
x - - Ф + I +
-x+3 + I + I + Ф -
2x+1 - Ф + I + I +
P + I - I + I -
S= ] -∞; -1/2 [ ∪ ] 0;3[
(2x - 1) (4 -5x) (x+2) tu fais pareil mais fais attention aux crochets, ils sont fermés.