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Laura23
@Laura23
May 2019
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URGENT !!! Bonjour j'ai besoin d'aide s.v.p Merci d'avance
Se ramener à une inéquation produit, puis la résoudre
x*( au cube) < 4x
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nadiab
Bonjour,
x³ < 4x
x³-4x < 0
x(x²-4) < 0
x(x-2)(x+2) < 0
x=0
ou
x=2
ou
x=-2
x I -
∞ -2 0 2 +∞
x - - + +
x-2 - - - +
x+2 - + + +
P - + - +
S= ]-
∞; -2[ ∪]0; 2[
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x³ < 4x
x³-4x < 0
x(x²-4) < 0
x(x-2)(x+2) < 0
x=0
ou
x=2
ou
x=-2
x I -∞ -2 0 2 +∞
x - - + +
x-2 - - - +
x+2 - + + +
P - + - +
S= ]-∞; -2[ ∪]0; 2[