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Yassmine68
@Yassmine68
April 2019
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URGENT, C'EST POUR DEMAIN ET C'EST NOTE, pouvez vous m'aider à faire mon exercice de maths s'il vous plaît? Merci à ceux qui m'aideont
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slyz007
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A) Dans un triangle la somme des angles fait 180°.
Donc ACH+CHA+HAC=180. Or CHA=90° donc
ACH=180-90-HAC=90-HAC
b) ABC=BAH+HAC or ABC=90° donc
BAH=90-HAC
c) ACH=BAH=90-HAC
d) TanACH=AH/HC=4,8/6,4=(3*1,6)/(4*1,6)=3/4
e) TanBAH=BH/AH=BH/4.8
f) ACH=BAH donc TanACH=TanBAH=3/4
Donc BH/4,8=3/4 et BH=3/4*4.8=3.6
g) TanACH=3/4 donc ACH=37° (arrondi au degré)
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Verified answer
A) Dans un triangle la somme des angles fait 180°.Donc ACH+CHA+HAC=180. Or CHA=90° donc
ACH=180-90-HAC=90-HAC
b) ABC=BAH+HAC or ABC=90° donc
BAH=90-HAC
c) ACH=BAH=90-HAC
d) TanACH=AH/HC=4,8/6,4=(3*1,6)/(4*1,6)=3/4
e) TanBAH=BH/AH=BH/4.8
f) ACH=BAH donc TanACH=TanBAH=3/4
Donc BH/4,8=3/4 et BH=3/4*4.8=3.6
g) TanACH=3/4 donc ACH=37° (arrondi au degré)