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manar67
@manar67
June 2021
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URGENT, pouvez vous m'aider s'il vous plait? Merci à ceux qui m'aideront
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pan59
Bonjour.
1) (a-b)² = (a-b)(a-b)
= a²-ab-ab+b² = a² - 2ab + b²
2) (a+b)(a-b) = a²-ab+ab-b² = a²-b²
Dans les 2 cas, les expressions sont égales.
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1) (a-b)² = (a-b)(a-b)
= a²-ab-ab+b² = a² - 2ab + b²
2) (a+b)(a-b) = a²-ab+ab-b² = a²-b²
Dans les 2 cas, les expressions sont égales.