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Lala19
@Lala19
April 2019
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URGENT SVP AIDEZ MOI!!
énoncé exercice:
On dissout 100mL de chlorure d'hydrogène dans 750mL d'eau. Le volume molaire du gaz est de 25L.mol-1
Calculer le pH de la solution d'acide chlorhydrique obtenue???
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Loverseries
100 mL = 0.1 L
0.1 L * 25 L.mol-1 = 2.5 mol.
Tu dissous donc 2.5 mol dans 750 mL d'eau.
[H+] = n / V = 2.5 / 0.750 = 3.33
pH = -log ([H+]) = -0.52
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Lista de comentários
0.1 L * 25 L.mol-1 = 2.5 mol.
Tu dissous donc 2.5 mol dans 750 mL d'eau.
[H+] = n / V = 2.5 / 0.750 = 3.33
pH = -log ([H+]) = -0.52