4x²-25=(2x+5)(x+1) ou (2x-5)(2x+5) = (2x+5)(x+1)
ou 2x+5=0 x= -5/2
ou 2x-5 = x +1 x = 6 solutions -5/2 et 6
(x+1)/(x-1) - (x-1/) (x+1) =4/(x²-1) x ne vaut ni 1 ni -1
(x+1)(x²-1) /(x-1) - (x-1)(x²-1) /(x+1)= 4
comme x² - 1 =(x-1)(x+1)
(x+1)(x+1) - (x-1)(x-1) = 4
x²+ 2x +1 -(x²-2x+1)= 4
4x = 4
x=1 c'est impossible pas de solution
Copyright © 2025 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
4x²-25=(2x+5)(x+1) ou (2x-5)(2x+5) = (2x+5)(x+1)
ou 2x+5=0 x= -5/2
ou 2x-5 = x +1 x = 6 solutions -5/2 et 6
(x+1)/(x-1) - (x-1/) (x+1) =4/(x²-1) x ne vaut ni 1 ni -1
(x+1)(x²-1) /(x-1) - (x-1)(x²-1) /(x+1)= 4
comme x² - 1 =(x-1)(x+1)
(x+1)(x+1) - (x-1)(x-1) = 4
x²+ 2x +1 -(x²-2x+1)= 4
4x = 4
x=1 c'est impossible pas de solution