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Mimi167
@Mimi167
April 2019
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Voici la deuxieme partie de mon exercice
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grr12
Tang ACB^= 5/12 = 0,416667
d'où ACB^ = 22,62 degrés
A=x^2 + 10 x = 25
B= 9x^2 - 42x + 49
C= x^2 - 16
D= 81 b^2 + 126 b + 49
E = 49 x^2 - 1
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mimi167
merci merci beaucoup
mimi167
je comprend pas les ^
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svp pouver vous me faire mon anglais je ny comprend rien merci baucoup
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Lista de comentários
d'où ACB^ = 22,62 degrés
A=x^2 + 10 x = 25
B= 9x^2 - 42x + 49
C= x^2 - 16
D= 81 b^2 + 126 b + 49
E = 49 x^2 - 1