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Laurebelleville227
@Laurebelleville227
May 2020
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Vous pouvez m’aider pour le 2 et le 3 svppppp
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swnn
2. (4x-3)²-9
= (4x-3)²-3²
= (4x-3+3)(4x-3-3)
= 4x(4x-6)
3. (4x-3)²-9 = 0
4x(4x-6) = 0
→ le produit de 2 facteurs est nul, si l’un de ses facteurs est nul:
4x=0 ou 4x-6=0
x=0 ou 4x=6
x=6/4=3/2
S = {0;3/2}
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laurebelleville227
Merci infiniment
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Lista de comentários
= (4x-3)²-3²
= (4x-3+3)(4x-3-3)
= 4x(4x-6)
3. (4x-3)²-9 = 0
4x(4x-6) = 0
→ le produit de 2 facteurs est nul, si l’un de ses facteurs est nul:
4x=0 ou 4x-6=0
x=0 ou 4x=6
x=6/4=3/2
S = {0;3/2}