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Trozerck
@Trozerck
May 2019
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Vous pouvez m'aider svp ?C'est l'exercice 62
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nadiab
Bonjour,
A= (x+3)(5x+9x²)
A= x(x+3)(5+9x)
B= (2-x)(4x-7)
C= (5-x)(8+1)
C= 9(5-x)
D= (2x+3)(x+1)
1 votes
Thanks 1
wissal1234m
A=5x(x+3)+9x°2(x+3)
A=(x+3)(5x+9x°2)
A=(x+3)(x)(5+9x)
B=(2-x)(4x)-7(2-x)
B=(2-x)(4x-7)
C=8(5-x)+(5-x)
C=(5-x)(8+1)
C=(5-x)(9) si tu veux u peux finir l'equation
D=2x+3+x(2x+3)
D=(2x+3)(1+x)
1 votes
Thanks 0
wissal1234m
oui car c'est une factorisation genre si tu veux finir si on te dit developpe
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Lista de comentários
A= (x+3)(5x+9x²)
A= x(x+3)(5+9x)
B= (2-x)(4x-7)
C= (5-x)(8+1)
C= 9(5-x)
D= (2x+3)(x+1)
A=(x+3)(5x+9x°2)
A=(x+3)(x)(5+9x)
B=(2-x)(4x)-7(2-x)
B=(2-x)(4x-7)
C=8(5-x)+(5-x)
C=(5-x)(8+1)
C=(5-x)(9) si tu veux u peux finir l'equation
D=2x+3+x(2x+3)
D=(2x+3)(1+x)