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KoloMenek
@KoloMenek
April 2019
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(x-2)(x-3) ca fait quoi ?
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Maldox
Utilise la double distributivité :
(x-2)(x-3) = x*x + x*(-3) + (-2)*x + (-2)*(-3)
= x² - 3x -2x + 6
= x² -5x + 6
3 votes
Thanks 2
Maldox
Oups je me suis trompé, ce n'est pas ça :(
Maldox
Alors, (x-2)(x-3) = x*x + x*(-3) + (-2)*x + (-2)*(-3)
Maldox
= x² -3x -2x + 6 = x²-5x + 6 :)
Maldox
Voilà c'est bon !
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(x-3)(x+3) ca fait quoi ????
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(x-2)(x-3) = x*x + x*(-3) + (-2)*x + (-2)*(-3)
= x² - 3x -2x + 6
= x² -5x + 6