je suis pas très sur =) en espérer t'avoir aider :)
(x-3)(2x+3) = x × 2x + x × 3 - 3 × 2x - 3
= 2x² + 3x - 6x - 3
= 2x² - 3x - 3
pour x = 3 :
(3-3)(2×3+3) = (3-3)(6+3)
= 3 × 6 + 3 × 3 - 3 × 6 - 3 × 3
= 18 + 9 - 18 - 9
= 0
pour x = 0 :
(3-3)(0×3+3) = (2×0-3)(0+3)
= 0 × 0 + 0 × 3 - 3 × 0 - 3 × 3
= 0 + 0 - 0 - 9
= -9
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Pour x = 3 on a :( x-3) ( 2x+3) = (3-3) (2×3+3) = 0 (6+3) = 0
Pour x = 0
( x-3) ( 2x+3) = (0-3) ( 2×0+3) = (-3) (0+3) = -3 × 3 = -9
je suis pas très sur =) en espérer t'avoir aider :)
(x-3)(2x+3) = x × 2x + x × 3 - 3 × 2x - 3
= 2x² + 3x - 6x - 3
= 2x² - 3x - 3
pour x = 3 :
(3-3)(2×3+3) = (3-3)(6+3)
= 3 × 6 + 3 × 3 - 3 × 6 - 3 × 3
= 18 + 9 - 18 - 9
= 0
pour x = 0 :
(3-3)(0×3+3) = (2×0-3)(0+3)
= 0 × 0 + 0 × 3 - 3 × 0 - 3 × 3
= 0 + 0 - 0 - 9
= -9