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matrixlumix
@matrixlumix
April 2022
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lim x² + 5x - 4 / x² - 5 x tende a 3
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HeliaV
Lim (x²+5x-4)/(x²-5) x->3
lim(3²+5*3-4)/(3²-5) x->3
lim 20/4 x->3 = 5
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Segue arquivo anexo, favor ajudar.
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(1/3)^ 3x-1<(1/3)^ x+5
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lim(3²+5*3-4)/(3²-5) x->3
lim 20/4 x->3 = 5