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Dareen
@Dareen
April 2019
1
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J'ai du mal sur une primitive
2/x - ln(x)/x
merci d'avance
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anylor
Méthode
2 * 1/x - ln(x) * 1/x
la primitive de 1/x c'est ln(x)
donc primitive de 2/x = 2ln(x)
pour ln(x) / x = ln * 1/x
forme u *u' -> primitive u (n+1) / (n+1)
u = lnx
u' =1/x
donc pour la primitive, on utilise la formule
u ^(n+1) / (n+1)
( on a posé u =lnx)
(lnx)^ (1+1) / 2
en définitive
2lnx -( lnx) ² / 2
1 votes
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Dareen
c'était ça merci
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Lista de comentários
2 * 1/x - ln(x) * 1/x
la primitive de 1/x c'est ln(x)
donc primitive de 2/x = 2ln(x)
pour ln(x) / x = ln * 1/x
forme u *u' -> primitive u (n+1) / (n+1)
u = lnx
u' =1/x
donc pour la primitive, on utilise la formule
u ^(n+1) / (n+1)
( on a posé u =lnx)
(lnx)^ (1+1) / 2
en définitive
2lnx -( lnx) ² / 2