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Mathildeburlet2
@Mathildeburlet2
May 2019
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Bonjours j'aurais besoin d'aide pour résoudre l'inéquation (1/x) + x inférieur ou égal à 0
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gilles2016
1/x + x ≤ 0 ⇔ x²+ 1 / x ≤0
Or x²+1 > 0 , donc
x²+ 1 / x ≤0
⇔ x < 0
Donc l'ensemble solutions est :
]-∞ ; 0 [
Bon courage !
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Lista de comentários
Or x²+1 > 0 , donc x²+ 1 / x ≤0 ⇔ x < 0
Donc l'ensemble solutions est : ]-∞ ; 0 [
Bon courage !