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Titi56fun
@Titi56fun
April 2019
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Bonsoir, pourriez-vous m'aider à résoudre cette équation merci :)
4,02 = [ ( x - 1) * 4 + 5 ] / x
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Commentaires (2)
4,02 = [(x - 1) * 4 + 5] / x (avec x ≠ 0)
4,02 = (4x - 4 + 5) / x
4,02 = (4x + 1)/x
(4x + 1)/x - (4,02x)/x = 0
(4x + 1 - 4,02x)/x = 0
- (0,02x + 1) / x = 0
Un quotient est nul si son numérateur est nul.
0,02x - 1 = 0
0,02x = 1
x = 1 / 0,02
x = 50
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4,02 = (4x - 4 + 5) / x
4,02 = (4x + 1)/x
(4x + 1)/x - (4,02x)/x = 0
(4x + 1 - 4,02x)/x = 0
- (0,02x + 1) / x = 0
Un quotient est nul si son numérateur est nul.
0,02x - 1 = 0
0,02x = 1
x = 1 / 0,02
x = 50