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CarlM
@CarlM
May 2019
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-x2 -128 - 3952=(x-52)(76-x)
Démontrer que les deux fonctions sont égaux.MERCI
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maudmarine
Verified answer
Bonjour,
- x² - 128x - 3952 = (x - 52) (76 - x)
(x - 52) (76 - x)
= 76x - x² - 3952 + 52x
= - x² + 128x - 3952
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nini999
Verified answer
Bonjour :
-x² + 128x - 3952 = (x - 52)(76 - x)
-x² + 128x - 3952 = 76x - x² - 3952 + 52x
-x²
+ 128x - 3952 = -x² + 76x + 52x - 3952
-x² + 128x - 3952 = -x² + 128x - 3952
J’espère t'avoir t'aider
1 votes
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nini999
Merci pour le meilleure réponse :)
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CarlM
May 2019 | 0 Respostas
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Lista de comentários
Verified answer
Bonjour,- x² - 128x - 3952 = (x - 52) (76 - x)
(x - 52) (76 - x)
= 76x - x² - 3952 + 52x
= - x² + 128x - 3952
Verified answer
Bonjour :-x² + 128x - 3952 = (x - 52)(76 - x)
-x² + 128x - 3952 = 76x - x² - 3952 + 52x
-x² + 128x - 3952 = -x² + 76x + 52x - 3952
-x² + 128x - 3952 = -x² + 128x - 3952
J’espère t'avoir t'aider