Articles
Register
Sign In
Search
CarlM
@CarlM
May 2019
2
75
Report
-x2 -128 - 3952=(x-52)(76-x)
Démontrer que les deux fonctions sont égaux.MERCI
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
maudmarine
Verified answer
Bonjour,
- x² - 128x - 3952 = (x - 52) (76 - x)
(x - 52) (76 - x)
= 76x - x² - 3952 + 52x
= - x² + 128x - 3952
0 votes
Thanks 0
nini999
Verified answer
Bonjour :
-x² + 128x - 3952 = (x - 52)(76 - x)
-x² + 128x - 3952 = 76x - x² - 3952 + 52x
-x²
+ 128x - 3952 = -x² + 76x + 52x - 3952
-x² + 128x - 3952 = -x² + 128x - 3952
J’espère t'avoir t'aider
1 votes
Thanks 1
nini999
Merci pour le meilleure réponse :)
More Questions From This User
See All
CarlM
May 2019 | 0 Respostas
Responda
×
Report "-x2 -128 - 3952=(x-52)(76-x)Démontrer que les deux fonctions sont égaux.MERCI.... Pergunta de ideia de CarlM"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Bonjour,- x² - 128x - 3952 = (x - 52) (76 - x)
(x - 52) (76 - x)
= 76x - x² - 3952 + 52x
= - x² + 128x - 3952
Verified answer
Bonjour :-x² + 128x - 3952 = (x - 52)(76 - x)
-x² + 128x - 3952 = 76x - x² - 3952 + 52x
-x² + 128x - 3952 = -x² + 76x + 52x - 3952
-x² + 128x - 3952 = -x² + 128x - 3952
J’espère t'avoir t'aider