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polianaparticular
@polianaparticular
July 2022
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PLEASE!
Resolva as equações em IR.
a) 25x^2+12/5x^2=47/3
b) x^2/x^2-9+ x^2/x^2-16=1
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emicosonia
Verified answer
PLEASE!
a) 25x^2+12/5x^2=47/3
a)
25x² + 12/5x² = 47/3
12 47
25x² + -----x² = ------- mmc = 5x3 = 15
5 3
15(25x²) + 3(12x²) = 5(47)
----------------------------------- FRAÇÃO com igualdade despreza o denominador
15
15(25x²) + 3(12x²) = 5(47)
375x² + 36x² = 235
411x² = 235
x² = 235/411
x =
+
√235/411
235 √235 √235(√411) √235x411 √96.585
x =
+
√--------- = ----------- = ----------------= ----------------- = ------------
411 √411 √411(√411) √411x411
√411²
lembrete:
elimina a √(raiz) com o (²)) -->(√411²) = 411
√96.585 fatora 96.585| 3
------------ 32,195| 5
411 6.439| 6.439
1/
lembrete: 3,5,6439 são números PRIMOS
√96.585
x' = + ------------
411
√96.585
x" = --------------
411
b) x^2/x^2-9+ x^2/x^2-16=1
b)
x²/x² - 9 + x²/x² - 16 = 1
x² x²
--- - 9 + --------- - 16 = 1 mmc = x²
x² x²
1(x²) - (x²)(9) + 1(x²) - (x²)16 = (x²)1
------------------------------------------------ FRAÇÃO com igualdade DESPREZA o
x² denominador
1(x²) - (x²)(9) + 1(x²) - (x²)16 = (x²)1
1x² - 9x² + 1x² - 16x² = 1x²
1x² + 1x² - 9x² - 16x² = 1x²
2x² - 25x² = 1x²
- 23x² = 1x²
-23x² - 1x² = 0
- 24x² = 0
x² = 0/24
x² = 0
x = √0
x = 0
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Verified answer
PLEASE!a) 25x^2+12/5x^2=47/3
a)
25x² + 12/5x² = 47/3
12 47
25x² + -----x² = ------- mmc = 5x3 = 15
5 3
15(25x²) + 3(12x²) = 5(47)
----------------------------------- FRAÇÃO com igualdade despreza o denominador
15
15(25x²) + 3(12x²) = 5(47)
375x² + 36x² = 235
411x² = 235
x² = 235/411
x = + √235/411
235 √235 √235(√411) √235x411 √96.585
x = + √--------- = ----------- = ----------------= ----------------- = ------------
411 √411 √411(√411) √411x411 √411²
lembrete: elimina a √(raiz) com o (²)) -->(√411²) = 411
√96.585 fatora 96.585| 3
------------ 32,195| 5
411 6.439| 6.439
1/
lembrete: 3,5,6439 são números PRIMOS
√96.585
x' = + ------------
411
√96.585
x" = --------------
411
b) x^2/x^2-9+ x^2/x^2-16=1
b)
x²/x² - 9 + x²/x² - 16 = 1
x² x²
--- - 9 + --------- - 16 = 1 mmc = x²
x² x²
1(x²) - (x²)(9) + 1(x²) - (x²)16 = (x²)1
------------------------------------------------ FRAÇÃO com igualdade DESPREZA o
x² denominador
1(x²) - (x²)(9) + 1(x²) - (x²)16 = (x²)1
1x² - 9x² + 1x² - 16x² = 1x²
1x² + 1x² - 9x² - 16x² = 1x²
2x² - 25x² = 1x²
- 23x² = 1x²
-23x² - 1x² = 0
- 24x² = 0
x² = 0/24
x² = 0
x = √0
x = 0