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October 2020
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calculando o limite x-->3 x2 -8x+15 /x2-9
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lim x2 -8x+15 ==>
(x-3)(x - 5)
=
x - 5
=
3 - 5
= -
2
ou -
1
x-->3 x2-9 (x+3)(x-3) x + 3 3 + 3 6 3
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3478elc
Verified answer
x² -8x+15/ x²-9
x² - 8x +15/ (x-3)(x+3)
(x-3)(x-5)/(x-3)(x+3)
(x-5)/(x+3)
Jogando o valor de x como 3, agora temos:
(3-5)/(3+3)
-2/6
-1/3 <--- resposta.
Espero que tenha entendido o que eu fiz, qualquer coisa só pergunta.
boa noite
0 votes
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Lista de comentários
lim x2 -8x+15 ==> (x-3)(x - 5) = x - 5 = 3 - 5 = - 2 ou - 1
x-->3 x2-9 (x+3)(x-3) x + 3 3 + 3 6 3
Verified answer
x² -8x+15/ x²-9x² - 8x +15/ (x-3)(x+3)
(x-3)(x-5)/(x-3)(x+3)
(x-5)/(x+3)
Jogando o valor de x como 3, agora temos:
(3-5)/(3+3)
-2/6
-1/3 <--- resposta.
Espero que tenha entendido o que eu fiz, qualquer coisa só pergunta.
boa noite