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Cocotebleu
@Cocotebleu
April 2019
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Montrer que si A(x)= x - 1 - 3/x+2 pour tout x différent de -2, alors A(x)= x²+x-5/x+2
URGENT svp :)
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A(x)=x-1-3/(x+2)
=((x-1)(x+2)-3)/(x+2)
=(x²-x+2x-2-3)/(x+2)
=(x²+x-5)/(x+2)
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Thanks 1
cocotebleu
merci beaucoup Pytagoras
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URGENT pour l'exercice 2 svp aidez moi !!
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=((x-1)(x+2)-3)/(x+2)
=(x²-x+2x-2-3)/(x+2)
=(x²+x-5)/(x+2)